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Friday, September 25, 2020

ROOT AND POWER




When a quantity m is raised to power in. It means that the quantity m should be multiple in the number of times of n 



Mⁿ = m₁ x m₂ x m₃...mₙ


2³ = 2 x2 x2 



From the above examples we can see that power gives the number of times the base is to be used as a factor. Power is also known to be an index or exponent.


Base -------X ʸ⁻⁻⁻⁻⁻⁻ power ( index)



8² mean 8 is raised to the power of 2 or 8 required 


z³ = means z cubed


2⁵  means fifth power of two


*Rule of  powers*


1. When a negative base is raised to an even power. it gives a positive result.


a.  (-2)² = (-2) x (-2)      =+4   


b. (-3)⁴ = (-3) x (-3) x (-3) x (-3) = +81


ii. when a negative base is raised to an odd number, it gives a negative result 


a.  (-2)³ = (-2) x (-2) x (-2) = -8


b. (-3)⁵ = (-3) x (-3) x (-3) x (-3)x (-3) = -243



iii. When a positive base is raiaed to either even or odd number, the result is positive.

a.  (-2)³ = (-2) x (-2) x (-2) = -8


b. (-3)⁵ = (-3) x (-3) x (-3) x (-3)x (-3) = -243



iii. When a positive base is raiaed to either even or odd number, the result is positive.


a. 2³ = 2 x 2 x 2 = 8


b.  3⁴ = 3 x 3 x3 x3 = 

     81


When any base ( except zero ) is raised to zero power , the result is positive one


a. x⁰ = 1

b. (-10)⁰ = 1

note 0⁰  = 1



When a base is raised to a negative power, the result is reciprocal of the base of the  base of the original number raised to the positive of that  power


a⁻ˣ = 1/aˣ


  *Worked examples*


Evaluate the following


I.   4² = 4 × 4 = 16 


II.  (-4)² = -4 × -4 = 16


III. 2² x (-3)³

  = -2 x -2 x(-3)(-3)(-3)

= -4 x (-27)

= 108



iv. (3)⁻² x (-2)3



2. Given that x=3, y= -1, and z = -2. Evaluate

x³ + y³ + z³


(3)³ + (-1)³ + (-2)³


27 + (-1) + (-8)


 = 18


ROOT


A root is obtained when a base is raised to a positive fraction power. The fractional power forms. Study the below question carefully



WORKED EXAMPLES


Find the value of y in each of the following 



Z^1/n  = ⁿ√(Z)


Where ( ^) means  ofpower of


1. 8^⅓ = ³√(8) 

= ³√(2 x 2 x 2) 

= 2


Example 2

What is the value of 

y⁴ = 81


add cube root to both side


⁴√(y⁴) = ⁴√(81)


Note: its only a fourth root that can cancel fourth power of y .We need to establish (y) alone


Hence,

y = ⁴√(81)


y = ⁴√(3 x 3 x3 x3)


y = ⁴√(3)⁴


y = 3




now you can see that its the fractional power of a number that forms its root and that the root of a number equals (=) to  one of its equal factors. 


*Rules of roots*


Given that y = ⁿ√(z)


a.   If n is a even number and y > 0, y will have two real solution, but if n is odd, y will have only two solution



Exampe 3


y² = 9 


add squared roots to both side


and so y = 


√(9) = + 3 or -3




4.   y³ = 64 


add cube root to both side


³√(y³) = ³√(64)


y = ³√(4 x 4 x4)


y = ³√(4³)


and so y 

y = 4




b. If n is an even number and y <0, z will have no real root, but if n is an odd number and y < 0, z will have only one z (negative) root


Example 5


a. y² = -4, and so y = √(-4) = No real root


b. y³ = - 8, 

and so x

 = ³√(8) =

- 2




Example 7


i √(7056)


 √(16 x 441)


√(16) x √(441)


4 x 21 = 84


ii. √(14400)

√(441 x 100)

= √(441) x √(100)

= 12 x 10 =120


iii. ³√(-2744)


³√(-8 x 343)


= ³√(-8) x ³√(343)


     -2 x  7 = -14


Example 8


if p = -7 and q = -2, find


a. (p-q)(p+q)


[(-7)-(-3)][(-7) + (-2)]


(-7 +3)(-7 - 2)


(-4)(-9)

=36

 

b.  p² - 2pq + q²


= (p -q)(p-q)


  [ (-7)-(-2)][(-7)-(-2)]

 

(-7 +2)(-7 +2)


= (-5)(-5) = 25




c. p + 2q - p²


(-7) + (2 x -2) - (-7)²


-7 + (-4) - (49)


-7 -4 -49


-60


SEE LINEAR INEQUALITIES

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